Intersection of a pair of linesLet L1 and L2 be a pair of lines, both in a projective plane and expressed in homogeneous coordinates:
where m1 and m2 are slopes and b1 and b2 are y-intercepts. Moreover let g be the duality mapping which maps lines onto their dual points. Then the intersection of lines L1 and L2 is point P3 where Determining the line passing through a pair of pointsLet P1 and P2 be a pair of points, both in a projective plane and expressed in homogeneous coordinates:
Let g−1 be the inverse duality mapping: which maps points onto their dual lines. Then the unique line passing through points P1 and P2 is L3 where Checking for incidence of a line on a pointGiven line L and point P in a projective plane, and both expressed in homogeneous coordinates, then P⊂L if and only if the dual of the line is perpendicular to the point (so that their dot product is zero); that is, if where g is the duality mapping. An equivalent way of checking for this same incidence is to see whether is true. ConcurrenceThree lines in a projective plane are concurrent if all three of them intersect at one point. That is, given lines L1, L2, and L3; these are concurrent if and only if If the lines are represented using homogeneous coordinates in the form m:b:1]L with m being slope and b being the y-intercept, then concurrency can be restated as Theorem. Three lines L1, L2, and L3 in a projective plane and expressed in homogeneous coordinates are concurrent if and only if their scalar triple product is zero, viz. if and only if Proof. Letting g denote the duality mapping, then The three lines are concurrent if and only if According to the previous section, the intersection of the first two lines is a subset of the third line if and only if Substituting equation (1) into equation (2) yields but g distributes with respect to the cross product, so that and g can be shown to be isomorphic w.r.t. the dot product, like so: so that equation (3) simplifies to CollinearityThe dual of concurrency is collinearity. Three points P1, P2, and P3 in the projective plane are collinear if they all lie on the same line. This is true if and only if but if the points are expressed in homogeneous coordinates then these three different equations can be collapsed into one equation: which is more symmetrical and whose computation is straightforward. If P1 : (x1 : y1 : z1), P2 : (x2 : y2 : z2), and P3 : (x3 : y3 : z3), then P1, P2, and P3 are collinear if and only if i.e. if and only if the determinant of the homogeneous coordinates of the points is equal to zero. See also
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