DefinitionsLet K be a field, and let A be a vector space over K equipped with an additional binary operation from A × A to A, denoted here by juxtaposition (i.e. if x and y are any two elements of A, xy is the product of x and y). Then if the binary operation is bilinear, which means that the following identities hold for any three elements x, y, and z of A, and all elements ("scalars") a and b of K:
we call A an algebra over K, we say that A is a K-algebra, and K is the base field of A. The binary operation is often referred to as multiplication in A. According to the convention adopted in this article (see above), multiplication of elements of A is not necessarily associative. More generally, algebras can be defined over an arbitrary commutative ring K instead of a field. In this case A forms a K-module, with bilinear multiplication again satisfying the above identities. In this case, A is a K-algebra, and K is the base ring of A. Given K-algebras A and B, a K-algebra homomorphism is a K-linear map f: A → B such that f(xy) = f(x) f(y) for all x,y in A. The space of all K-algebra morphisms is frequently written as A K-algebra isomorphism is a bijective K-algebra morphism. For all practical purposes, isomorphic algebras differ only by notation. Kinds of algebras and examplesA commutative algebra is one whose multiplication is commutative; an associative algebra is one whose multiplication is associative. These include the most familiar kinds of algebras.
The best-known kinds of non-associative algebras are those which are nearly associative, that is, in which some simple equation constrains the differences between different ways of associating multiplication of elements. These include:
More classes of algebras:
Algebras and ringsThe definition of an associative K-algebra with unit is also frequently given in an alternative way. In this case, an algebra over a field K is a ring A together with a ring homomorphism where Z(A) is the center of A. Since η is a ring morphism, then one must have either that A is the trivial ring, or that η is injective. This definition is equivalent to that above, with scalar multiplication given by Given two such associative unital K-algebras A and B, a unital K-algebra morphism f: A → B is a ring morphism that commutes with the scalar multiplication defined by η, which one may write as
for all Structure coefficientsFor algebras over a field, the bilinear multiplication from A × A to A is completely determined by the multiplication of basis elements of A. Conversely, once a basis for A has been chosen, the products of basis elements can be set arbitrarily, and then extended in a unique way to a bilinear operator on A, i.e. so that the resulting multiplication will satisfy the algebra laws. Thus, given the field K, any algebra can be specified up to isomorphism by giving its dimension (say n), and specifying n3 structure coefficients ci,j,k, which are scalars. These structure coefficients determine the multiplication in A via the following rule: where e1,...,en form a basis of A. The only requirement on the structure coefficients is that, if the dimension n is infinite, then this sum must always converge (in whatever sense is appropriate for the situation). Note however that several different sets of structure coefficients can give rise to isomorphic algebras. When the algebra can be endowed with a metric, then the structure coefficients are written with upper and lower indices, so as to distinguish their transformation properties under coordinate transformations. Specifically, lower indices are covariant indices, and transform via pullbacks, while upper indices are contravariant, transforming under pushforwards. Thus, in mathematical physics, the structure coefficients are often written ci,jk, and their defining rule is written using the Einstein notation as
If you apply this to vectors written in index notation, then this becomes
If K is only a commutative ring and not a field, then the same process works if A is a free module over K. If it isn't, then the multiplication is still completely determined by its action on a set that spans A; however, the structure constants can't be specified arbitrarily in this case, and knowing only the structure constants does not specify the algebra up to isomorphism. See also
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